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To solve problems involving ratios of algebraic expressions (like (\frac{a+b}{a-b}) or (\frac{a^2+b^2}{a^2-b^2})), follow these steps:

Step 1: Let (x = \frac{a}{b})

This simplifies the ratio by reducing it to a single variable (x).

Step 2: Substitute (x = \frac{a}{b}) into the given ratio

For example, if the given ratio is (\frac{a+b}{a-b} = \frac{5}{3}):
[ \frac{x+1}{x-1} = \frac{5}{3} ]

Cross-multiply to solve for (x):
[ 3(x+1) = 5(x-1) ]
[ 3x + 3 = 5x -5 ]
[ 2x = 8 \implies x = 4 ]

Step 3: Compute the desired ratio

Suppose the desired ratio is (\frac{a^2 + b^2}{a^2 - b^2}):
[ \frac{x^2 +1}{x^2 -1} = \frac{4^2 +1}{4^2 -1} = \frac{16+1}{16-1} = \frac{17}{15} ]

Common Result: If (\frac{a+b}{a-b} = \frac{5}{3}), then (\frac{a^2 + b^2}{a^2 - b^2} = \frac{17}{15}).

Adjust the steps based on your specific problem, but this method applies to most ratio-based algebraic questions.

Answer: (\boxed{\dfrac{17}{15}}) (assuming the given ratio (\frac{a+b}{a-b} = \frac{5}{3}))
If your problem differs, use the above steps to compute the correct result.

(\boxed{17/15})

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